0.3x+0.005069x^2=127.008

Solution for 0.3x+0.005069x^2=127.008 equation:

0.3x+0.005069x^2=127.008

We move all terms to the left:

0.3x+0.005069x^2-(127.008)=0

We add all the numbers together, and all the variables

0.005069x^2+0.3x-127.008=0

a = 0.005069; b = 0.3; c = -127.008;
Δ = b2-4ac
Δ = 0.32-4·0.005069·(-127.008)
Δ = 2.665214208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{2.665214208}}{2*0.005069}=\frac{-0.3-\sqrt{2.665214208}}{0.010138}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{2.665214208}}{2*0.005069}=\frac{-0.3+\sqrt{2.665214208}}{0.010138}
$